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Old 12-12-2005, 09:42 PM
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The Hitter's Inclined Plane
Originally Posted by tongzilla

Do you think your post above is 100% compatible with Homer's comment:

"Delivery Lines can be "On Line" or "Cross Line" (2-J-3) -- Inside-out or Outside-in. All must be executed as Plane Lines with their individual Inclined Planes.

it's the "with their individual Inclined Planes" bit that's bugging me (or looking at it from another angle, it's your post that's bugging me ). You're saying that it should not be executed with its individual Inclined Plane
Yes, Leo, my post is 100 percent compatitible with your quote from 10-5-0. Obviously, the Swinger's On Line Stroke has its own Inclined Plane, so there's no concern there. Regarding the Hitter's Cross Line Stroke, I never said that the Angle of Approach Procedure did not have its own Inclined Plane, but only that its Baseline is Covered by the Clubhead, not Traced. In my post above (Trace or Cover?), I described that Plane as follows:

"Covering does indeed cause the Hitter's Plane to be steeper. However, it does not cause it to be Vertical. Instead, per 2-J-3, its Angle is dictated by the Clubshaft motions required for the Clubhead to cover the Angle of Approach and its extensions (before Impact Point and after Low Point)."

So, we're compatitble on that point, too.

Finally, the "Inside Out or Outside In" part of the quote refers to the fact that, regardless of how you set the Plane Line -- Square (10-5-A), Open (10-5-D) or Closed (10-5-E) -- the Delivery Lines are integral to the Plane (however aligned) and must be so executed. In other words, the relation of 'the Circle (Clubhead orbit) to the Line' will always produce an Inside-Out Impact (2-J-2), even with an Outside-In Stroke.
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