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Old 05-24-2006, 08:11 PM
neil neil is offline
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Join Date: Sep 2005
Location: Orlando.FL
Posts: 818
Originally Posted by Daryl
I agree that both planes intersect at the #3 pressure point. But the Left arm flying wedge requires a flat left wrist so that the clubshaft, wristcock, and left arm lie in the same flat plane.

You agree they intersect which implies two planes.
No -If I thought there were two planes I would say so .I think they intersect but the hands/clubshaft are subject to the rotation of the shoulders which takes the left arm "off plane"-but it has it's "own plane"which is not the inclined plane of the right forearm.An argument could be made that you would have to bend the left wrist to keep the back of the left hand parallel to the plane-and Homer did not dismiss this so long as you get it flat at impact.If the left wrist stays flat throughout the swing then I would say that it is the #3pp that can stay on the intersection of the "two planes"but that is still the selected plane -back- in -up- down -out- forward.Or for example the turned shoulder plane o.k. where are THE BIG GUNS!
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