On Forces active in the Golf Swing....

[drewitgolf]

Just if your interested:

Where Vfict (r) is the potential responsible for the
centrifugal force: fc = −ω×(ω×r) = (ω2−ω ωT)r
.
Vfict (r) = −1
2 rT(ω2 − ω ωT)r
Now, Rs and RJ are parallel and MsRs+MJRJ =
0.
[Note that if a particle is moving then addi-
tional Coriolis forces act that are not mentioned
in @
@rVeff (r), so we can’t determine stability from
Veff .

Any questions?

Yes Rob, are you sure that your calculation 2 rT(ω2 − ω ωT)r should not be 1.8 rT(ω2 − ω ωT)r ? Just wondering.