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Thread: Pivot center
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Old 12-24-2008, 12:07 PM
no_mind_golfer no_mind_golfer is offline
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Join Date: Oct 2008
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Originally Posted by Jeff View Post
nmgolfer

I like your mathematical expertise when dealing with problems in golf physics.

However, sometimes you get it wrong.
Yes... I'm the first to admit that, but not in this case.

Originally Posted by Jeff View Post
You wrote-: "Nope.... sometimes forces do no work and when the don't do work they can't contribute power (or store energy)

Lets step back.

Work is Force X Distance (has units of energy)
Power is Work / time."

Your formula is wrong when you state that work = force X distance.
NO IT IS NOT... THAT IS click->THE DEFINITION



Work ONLY gets done when it causes kinetic energy to change. If D (distance) is zero, no work gets done. Centripetal acceleration does not change the kinetic energy of a rotating body. IT DOES NO WORK.

Originally Posted by Jeff View Post
One also needs to consider the work force needed to stay in balance when moving in a circular manner. Centripetal force is constantly operating to keep an object in its circular track while traveling at a constant speed - and if the centripetal force is operant, then it is contributing to work (energy) output by preventing the object from flying off its circular path.

Consider two cars having a 100 miles race. Car A has to travel 100 miles on a straight track. If car A completes the race in 1 hour by traveling at 100mph, then car A has expended a certain amount of energy (work output) to complete the race in 1 hour. Now imagine car B having to travel 100 miles on a circular track. If car B completes the race in 1 hour by traveling at a constant speed of 100mph, then car B has expended much more energy (work output) in the same time than car A. The extra energy was expended in trying to keep the car on the circular track at all times while it was racing around a constantly present amount of road bend at 100mph. That extra energy is the centripetal force energy required to constantly centripetally accelerate the car (to constantly keep the car moving along a circular path, rather than a straight path).

Jeff.
NO BOTH CARS EXPEND THE SAME ENERGY. However the car on the track's tires would show more wear DUE TO FRICTION (the force that provided the click->centripetal force requirement )

Last edited by no_mind_golfer : 12-24-2008 at 12:21 PM. Reason: try to get hyperlinks to show