LynnBlakeGolf Forums - View Single Post - What's the ratio of hitters to swingers on tour?
View Single Post
  #7  
Old 06-24-2009, 10:11 PM
LINYGSEB LINYGSEB is offline
Junior Member
 
Join Date: May 2006
Posts: 5
Caveat to readers and questioners - I'm rusty, but I will try to explain. I'm not saying I am correct, just giving my take based on my understanding.

Hitting involves radial thrust, PP#3 into the inside aft quadrant. In order to accomplish this, the right arm needs to be at a 90 degree angle to the shaft.

At the top, hitters accumulate power by getting their right arm into a position to exert this thrust. The right arm needs to be at a 90 degree angle to the club. The angle of the arms at the top is by necessity, 90 degrees.

Swingers generate longitudinal force - they pull with the left arm and initiate PP#4, the left arm against the chest. Their arms are typically at less than right angles at the top.

So, Tiger's forearms at the top used to be closer together, consistent with swinger's procedure. Now, because he is flatter, they are farther apart, and the right forearm in at 90 degrees to the shaft.

Stay with me. Hitters activate accumulators 1, 2 and 3 by the thrust of the right arm - it happens based on a strong grip and you can see the club hop ever so briefly off the plane line.

Swingers activate acummulators 4, 2, and 3 based on centrifugal force. The club travels more on the plane and release is based on the pivot, I think.

So, if you get your right elbow into a position to drive, but then you pull, you have a problem.

Also, if you set up to drive and then release for a pull, you have a problem.

You can obviously make this work, but you need to compensate - which is like taxes.

I'm not clear on all of this, it's been a while, but I think there is validity to the thought.
Reply With Quote