Yoda - you wrote-: "Except as effected by Wristcock for Power considerations, the Hands and Clubhead ideally move in concentric circles. This is Rhythm!"
Un-huh! Especially in 10-23-A.
Thanks for sharing your opinion,
Now, I can go back to regular (I mean "reality") programming.
Yoda - you wrote-: "Except as effected by Wristcock for Power considerations, the Hands and Clubhead ideally move in concentric circles. This is Rhythm!"
Un-huh! Especially in 10-23-A.
Thanks for sharing your opinion,
Now, I can go back to regular (I mean "reality") programming.
Jeff.
Got it, Jeff.
Leave aside the fact that each of the Delivery Paths (10-23-A/B/C/D/E) have their separate identity from Rhythm . . .
Let your world continue to unfold as you see fit.
Thrill a minute on Spaceship Jeff!
P.S. And, hey, I like that flak jacket . . . It's you!
The different hand delivery paths get their separate identity from rhythm --- the rhythm between the i) torso rotational movement (including secondary axis tilt variations) and ii) the left arm rotational movement at the level of the left shoulder socket (including variations in left arm/hand plane shift during the left arm's rotational movement). Varying rhythm produces variably-shaped hand arc paths, and some of those hand arc paths are not perfectly circular in nature.
Doing my dead-level best to generate Lag Pressure, and . . .
Trace that Straight Plane Line.
If only I had known . . .
Originally Posted by jeff
The different hand delivery paths get their separate identity from rhythm --- the rhythm between the i) torso rotational movement (including secondary axis tilt variations) and ii) the left arm rotational movement at the level of the left shoulder socket (including variations in left arm/hand plane shift during the left arm's rotational movement). Varying rhythm produces variably-shaped hand arc paths, and some of those hand arc paths are not perfectly circular in nature.
I like your mathematical expertise when dealing with problems in golf physics.
However, sometimes you get it wrong.
You wrote-: "Nope.... sometimes forces do no work and when the don't do work they can't contribute power (or store energy)
Lets step back.
Work is Force X Distance (has units of energy)
Power is Work / time."
Your formula is wrong when you state that work = force X distance.
One also needs to consider the work force needed to stay in balance when moving in a circular manner. Centripetal force is constantly operating to keep an object in its circular track while traveling at a constant speed - and if the centripetal force is operant, then it is contributing to work (energy) output by preventing the object from flying off its circular path.
Consider two cars having a 100 miles race. Car A has to travel 100 miles on a straight track. If car A completes the race in 1 hour by traveling at 100mph, then car A has expended a certain amount of energy (work output) to complete the race in 1 hour. Now imagine car B having to travel 100 miles on a circular track. If car B completes the race in 1 hour by traveling at a constant speed of 100mph, then car B has expended much more energy (work output) in the same time than car A. The extra energy was expended in trying to keep the car on the circular track at all times while it was racing around a constantly present amount of road bend at 100mph. That extra energy is the centripetal force energy required to constantly centripetally accelerate the car (to constantly keep the car moving along a circular path, rather than a straight path).
Work ONLY gets done when it causes kinetic energy to change. If D (distance) is zero, no work gets done. Centripetal acceleration does not change the kinetic energy of a rotating body. IT DOES NO WORK.
Originally Posted by Jeff
One also needs to consider the work force needed to stay in balance when moving in a circular manner. Centripetal force is constantly operating to keep an object in its circular track while traveling at a constant speed - and if the centripetal force is operant, then it is contributing to work (energy) output by preventing the object from flying off its circular path.
Consider two cars having a 100 miles race. Car A has to travel 100 miles on a straight track. If car A completes the race in 1 hour by traveling at 100mph, then car A has expended a certain amount of energy (work output) to complete the race in 1 hour. Now imagine car B having to travel 100 miles on a circular track. If car B completes the race in 1 hour by traveling at a constant speed of 100mph, then car B has expended much more energy (work output) in the same time than car A. The extra energy was expended in trying to keep the car on the circular track at all times while it was racing around a constantly present amount of road bend at 100mph. That extra energy is the centripetal force energy required to constantly centripetally accelerate the car (to constantly keep the car moving along a circular path, rather than a straight path).
Jeff.
NO BOTH CARS EXPEND THE SAME ENERGY. However the car on the track's tires would show more wear DUE TO FRICTION (the force that provided the click->centripetal force requirement )
Last edited by no_mind_golfer : 12-24-2008 at 12:21 PM.
Reason: try to get hyperlinks to show
Sorry. I cannot accept your explanation. You eliminate the possibility of using centripetal force as being part of your work output equation by framing your equation in that manner. If you "a priori" exclude centripetal force, then obviously it seems that centripetal force doesn't require energy to become operant. The energy may not be utilised to generate forward momentum (forward kinetic energy) along the race track (in the car example), but energy is required to keep the car on a circular track (and the car's tires know that).
Consider a simple example.
Imagine traveling in a NYC subway car that is traveling at 40mph on a straight rail track. Imagine that you are standing in the center aisle and holding onto a vertical post. Then imagine what happens when the subway car goes around a tight bend at the same speed. You will have to hang onto that vertical post for "dear life" to prevent yourself from being catapulted down the length of the subway car. It requires "energy" to remain stationary in balance and that energy is the energy required to offset a centrifugal force acting on your body. I would imagine that the subway car also needs to expend energy to stay in balance on its circular track, and that energy is centripetal energy.
Sorry. I cannot accept your explanation. You eliminate the possibility of using centripetal force as being part of your work output equation by framing your equation in that manner. If you "a priori" exclude centripetal force, then obviously it seems that centripetal force doesn't require energy to become operant. The energy may not be utilised to generate forward momentum (forward kinetic energy) along the race track (in the car example), but energy is required to keep the car on a circular track (and the car's tires know that).
I'm sorry you're sorry you cannot accept my explanation but I assure you it is the one and only technically correct one. First off the force is called tension (axial load)... and it has two components (one in the normal, perpendicular to path i.e. centripetal direction and one in the tangential direction.) The normal component of the tension force does not move the object closer to the center of rotation and therefore it does NO WORK! The tangential component on the other hand accelerated the object along the path. The tangential component (and this is the one thing BerntR and I can agree on) is what does the work.
Originally Posted by Jeff
Consider a simple example.
Imagine traveling in a NYC subway car that is traveling at 40mph on a straight rail track. Imagine that you are standing in the center aisle and holding onto a vertical post. Then imagine what happens when the subway car goes around a tight bend at the same speed. You will have to hang onto that vertical post for "dear life" to prevent yourself from being catapulted down the length of the subway car. It requires "energy" to remain stationary in balance and that energy is the energy required to offset a centrifugal force acting on your body. I would imagine that the subway car also needs to expend energy to stay in balance on its circular track, and that energy is centripetal energy.
Jeff.
NO it does not require energy! It requires a FORCE (see click here->Centripetal force requirement. This is why we have a variety of words in the lexicon: FORCE WORK ENERGY etc. soforth.... They have different meanings. AGAIN.... SOME FORCES DO NO WORK.
If you are hanging motionless on a jungle gym there is a force in your arms .... but you're not doing work... you're not expending power... You're hanging there motionless. You don't do work until you do a pull up. When you do a pull-up you are moving that force (mass X gravity) through a distance ... THAT is work... THE requires Hp. Hanging Motionless does not..... but there is a FORCE present when you hang motionless... make no mistake about that!
I'm done with this one.... believe what you want to.... makes no difference to me really.... Merry Christmas Jeff
Hybrid Mode
